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5s-2=3s^2
We move all terms to the left:
5s-2-(3s^2)=0
determiningTheFunctionDomain -3s^2+5s-2=0
a = -3; b = 5; c = -2;
Δ = b2-4ac
Δ = 52-4·(-3)·(-2)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-1}{2*-3}=\frac{-6}{-6} =1 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+1}{2*-3}=\frac{-4}{-6} =2/3 $
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